Question
Let * be a binary operation on the set Q of rational numbers as follows:
a * b = ab2

Answer

a * b = ab2 and b * a = ba2 $\neq\text{a}*\text{b}$
$\therefore$ operation * is not commutative.
(a * b) * c = (ab2) * c = (ab2)c2 = ab2c2
And a * (b * c) = a * (bc2) = a(bc2)2 = ab2c4
Here, $(\text{a}*\text{b})*\text{c}=\text{a}*(\text{b}*\text{c})$
$\therefore$ operation * not is associative.

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