- A$-\frac{5}{2}$
- B$-2$
- C$-3$
- ✓$-\frac{3}{2}$
$\lim _{x \rightarrow 0^{+}} f(x)=f(0)=\lim _{x \rightarrow 0^{-}} f(x)....(1)$
$f(0)= b....(2)$
$\lim _{x \rightarrow 0^{+}} f(x)=\lim _{x \rightarrow 0^{+}}\left(\frac{\sin (a+1) x}{2 x}+\frac{\sin 2 x}{2 x}\right)$
$=\frac{a+1}{2}+1....(3)$
$\lim _{x \rightarrow 0^{+}} f(x)=\lim _{x \rightarrow 0^{+}} \frac{\sqrt{x+b x^{3}}-\sqrt{x}}{b x^{5 / 2}}$
$=\lim _{x \rightarrow 0^{+}} \frac{\left(x+b x^{3}-x\right)}{b x^{5 / 2}\left(\sqrt{x+b x^{3}}+\sqrt{x}\right)}$
$=\lim _{x \rightarrow 0^{+}} \frac{\sqrt{x}}{\sqrt{x}\left(\sqrt{1+b x^{2}}+1\right)}=\frac{1}{2} \quad \ldots(4)$
Use $(2),(3)$ And $(4)$ in $(1)$
$\frac{1}{2}=b=\frac{a+1}{2}+1$
$\Rightarrow b =\frac{1}{2}, a =-2$
$a+b=\frac{-3}{2}$
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(where $C$ is a constant of integration.)