MCQ
Let $f: R \rightarrow R$ be defined as $f(x) = 3x.$ Choose the correct answer.
  • $f$ is one$-$one onto
  • B
    $f$ is many$-$one onto
  • C
    $f$ is one$-$one but not onto
  • D
    $f$ is neither one$-$one nor onto.

Answer

Correct option: A.
$f$ is one$-$one onto
$f: R \rightarrow R$ is defined as $f(x) = 3x.$
Let $\text{x},\text{y}\in\text{R}$ such that $f(x) = f(y)$.
$\Rightarrow 3x = 3y$
$ \Rightarrow x = y$
$\therefore f$ is one$-$one.
Also, for any real number $(y)$ in $co-$domain $R,$ there exists $\frac{\text{y}}{3}$ in $R$
 such that $f\Big(\frac{\text{y}}{3}\Big)=3\Big(\frac{\text{y}}{3}\Big)=\text{y}$
$\therefore f$ is onto.
​​​​​​​Hence, function $f$ is one$-$one and onto.
The correct answer is $A.$

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