MCQ
Let $f(x)$ be a polynomial such that $\text{f}(-\frac{1}{2})=0,$ then a factor of $f(x)$ is:
- ✓$2x + 1$
- B$x - 1$
- C$x + 1$
- D$2x - 1$
✓
Answer
Correct option: A.
$2x + 1$
Let $f(x)$ be a polynomial such that $\text{f}(-\frac{1}{2})=0,$
i.e., $\text{x}+\frac{1}{2}=0$ is a factors.
On rearranging $\text{f}(-\frac{1}{2})=0 $ can be written as $(2x + 1) = 0$
Thus, $(2x + 1)$ is a factor of $f(x).$
i.e., $\text{x}+\frac{1}{2}=0$ is a factors.
On rearranging $\text{f}(-\frac{1}{2})=0 $ can be written as $(2x + 1) = 0$
Thus, $(2x + 1)$ is a factor of $f(x).$
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