MCQ
Let $f(x)=\left\{\begin{array}{cc}-2, & -2 \leq x \leq 0 \\ x-2, & 0 < x \leq 2\end{array}\right.$ and $h(x)=f(|x|)+|f(x)|$. Then $\int_{-2}^2 \mathrm{~h}(\mathrm{x}) \mathrm{dx}$ is equal to :
- ✓$2$
- B$4$
- C$1$
- D$6$
✓
Answer
Correct option: A.
$2$
a
$Image$
$Image$
$h(x)=\left\{\begin{array}{cc}x-2+2-x=0, & 0 \leq x \leq 2 \\ -x-2+2=-x & -2 \leq x<0\end{array}\right.$
$Image$
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