MCQ
Let $\lambda \in R$ and let the equation $E$ be $| x |^2-2| x |+|\lambda-3|=0$. Then the largest element in the set $S =$ $\{ x +\lambda: x$ is an integer solution of $E \}$ is $..........$
- A$4$
- B$3$
- ✓$5$
- D$2$
$| x |^2-2| x |+|\lambda-3|-1=0$
$(| x |-1)^2+|\lambda-3|=1$
At $\lambda=3, x =0$ and 2 ,
at $\lambda=4$ or 2, then
$x =1 \text { or }-1$
So maximum value of $x+\lambda=5$
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