MCQ
Let $\left| {\vec a} \right| = \left| {\vec b} \right| = \left| {\vec a - \vec b} \right| = \,1$ then angle between $\vec a$ and $\vec b$ is
- A$\frac{\pi }{6}$
- ✓$\frac{\pi }{3}$
- C$\frac{\pi }{4}$
- D$\frac{\pi }{2}$
$ \Rightarrow |\vec a{|^2} + |\vec b{|^2} - 2\left| {\vec a} \right|\left| {\vec b} \right|\cos \theta = 1$
$ \Rightarrow \cos \theta=1 / 2 \Rightarrow \cos \theta=1 / 2 $
$\Rightarrow \theta=\pi / 3$
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| $X$ | $c$ | $2c$ | $3c$ | $4c$ | $5c$ | $6c$ |
| $f$ | $2$ | $1$ | $1$ | $1$ | $1$ | $1$ |