MCQ
Let $m$ be the midpoint and $u$ be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is:
- ✓$2m - u$
- B$2m + u$
- C$m - u$
- D$m + u$
✓
Answer
Correct option: A.
$2m - u$
Given:
Mid value $= m$
Upper limit $= u$
We know,
$\frac{\text{Upper}\ \text{limit}+\text{Lower}\ \text{limit}}{2}=\text{Mid}\ \text{value}$
$\Rightarrow\frac{\text{Lower}\ \text{limit}+\text{u}}{2}=\text{m}$
$⇒$ Lower limit $+\ u = 2m$
$⇒$ Lower limit $= 2m - u$
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