MCQ
Let $P_m$ stand for $^nP_m$ . Then the expression $1 . P_1 + 2 . P_2 + 3 . P_3 + ..... + n . P_n =$
  • $(n + 1) ! - 1$
  • B
    $(n + 1) ! + 1$
  • C
    $(n + 1) !$
  • D
    none of these

Answer

Correct option: A.
$(n + 1) ! - 1$
a
$Tn = n . n ! = n ! [ (n + 1) - 1 ] = (n + 1) ! - n !$.

Now put $n = 1, 2, 3 , .......$ and add 

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the sum of the roots of the equation ${x^2} + px + q = 0$ is equal to the sum of their squares, then
Let the sequence ${a_1},{a_2},{a_3},.............{a_{2n}}$ form an $A.P. $ Then $a_1^2 - a_2^2 + a_3^3 - ......... + a_{2n - 1}^2 - a_{2n}^2 = $
Let $\text{A} = \{\text{x : x} \in \text{R}, \text{x > 4}\}$ and $\text{B}= \{\text{x}\in\text{R : x} < 5\}.$ Then, $\text{A}\cap\text{B}=$
  1. (4, 5]
  2. (4, 5)
  3. [4, 5)
  4. [4, 5].
Let A = {1, 2, 3, 4, 5} and R be a relation from A to A, R = {(x, y) : y = x + 1}. Find the domain:
The sum of all the natural numbers for which $log_{(4-x)}(x^2 -14x + 45)$ is defined is -
If p(n): $49^\text{n}+16^{\text{n}}\lambda$ is divisible by 64 for $\text{n}\in\text{N}$ is true, then the least negative integral value of $\lambda$ is:
For $0<\theta<\frac{\pi}{2}$, the solution(s) of $\sum_{m=1}^6 \operatorname{cosec}\left(\theta+\frac{(m-1) \pi}{4}\right) \operatorname{cosec}\left(\theta+\frac{m \pi}{4}\right)=4 \sqrt{2}$ is(are)

$(A)$ $\frac{\pi}{4}$ $(B)$ $\frac{\pi}{6}$ $(C)$ $\frac{\pi}{12}$ $(D)$ $\frac{5 \pi}{12}$

Let $f(x) = Ax^3 -Bx -tanx.sgn(x)$ be an even function $\forall \,\,x\, \in R - \left\{ {\left( {2n + 1} \right)\frac{\pi }{2},n \in I} \right\}$ , 

where $A = {\sin ^2}\alpha  - \sin \alpha  + \frac{1}{4}$

and    $B = {\tan ^2}\alpha  + \frac{2}{{\sqrt 3 }}\tan \alpha  + \frac{1}{3}$ , then the number of value $(s)$ of $\alpha $ in $\left[ { - \frac{{3\pi }}{2},2\pi } \right]$ is - (where $sgnx$ denotes signum function of $x$ )

If the value of $\lim _{x \rightarrow 0}(2-\cos x \sqrt{\cos 2 x})^{\left(\frac{x+2}{x^{2}}\right)}$ is equal to $e^{a}$, then $a$ is equal to $.....$
Seven of the eight numbers in a distribution are $11, 16,6, 10, 13, 11, 13$. Given that the mean of the distribution is $12,$ if $12$ will be included then find the new mean of the distribution.