Download App

Relations — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsRelations1 Mark
Question
Let R = {(a, a), (b, b), (c, c), (a, b)} be a relation on set A = a, b, c. Then, R is:
  1. Identify relation.
  2. Reflexive.
  3. Symmetric.
  4. Antisymmetric.
✓

Answer

  1. Reflexive.

Solution:

Reflexivity: Since $(\text{a, a})\in\text{R}\ \forall\ \text{a}\in\text{A},$ R is reflexive on A.

Symmetry: Since $(\text{a, b})\in\text{R}$ but $(\text{b, a})\notin\text{R,}$ is not symmetric on A.

⇒ R is not antisymmetric on A.

Also, R is not an identity relation on A.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Relations→Relations — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Let A = {1, 2, ......., n} and B = {a, b}. Then the number of subjections from A into B is:
  1. $^{\text{n}}\text{P}_2$
  2. $2^\text{n}-2$
  3. $2^\text{n}-1$
  4. $^{\text{n}}\text{C}_2$
→
The maximum value of Z = 4x + 2y subject to the constraints $2\text{x}+3\text{y}\leq18,\text{x}+\text{y}\geq10,\text{x},\text{y}\leq0$ is:
  1. 36
  2. 40
  3. 30
  4. None of these
→
Choose the correct answer from the given four options.
The probability of guessing correctly at least 8 out of 10 answers on a true-false type examination is:
→
The unit vector perpendicular to the vectors $i - j + k$ and $2i + 3j - k$ is
→
The value of $x$  obtained from the equation $\left| {\,\begin{array}{*{20}{c}}{x + \alpha }&\beta &\gamma \\\gamma &{x + \beta }&\alpha \\\alpha &\beta &{x + \gamma }\end{array}\,} \right| = 0$ will be
→
A stone throw upward having speed equation $S =9.8 t-4.9 t^2$ where S in $m / s$. What will be the time to achieve maximum height ?
→
$\int_0^{2\pi } {\frac{{\sin 2\theta }}{{a - b\,\cos \theta }}\,d\theta = } $
→
If $\sin^{-1}\text{x}-\cos^{-1}\text{x}=\frac{\pi}{6},$ then x =
  1. $\frac{1}{2}$
  2. $\frac{\sqrt{3}}{2}$
  3. $-\frac{1}{2}$
  4. $-\frac{\sqrt{3}}{2}$
→
The value of $\Delta=\left|\begin{array}{ccc}3 & 7 & 13 \\ -5 & 0 & 0 \\ 0 & 11 & -2\end{array}\right|$ is
→
$\int_{-2}^{2}|\text{x}|\text{dx}=$
  1. 0
  2. 2
  3. 1
  4. 4
→