Question
Let $R$ be a relation in the set $N$ given by $R=\{(a, b): a=b-2, b>6\}$. Then

Answer

(b) : Given, $R=\{(a, b): a=b-2, b>6\}$
Since, $b>6$, so $(2,4) \notin R$
Also, $(3,8) \notin R$ as $3 \neq 8-2$
and $(8,7) \notin R$ as $8 \neq 7-2$
Now, for $(6,8)$, we have
$8>6$ and $6=8-2$, which is true
$\therefore \quad(6,8) \in R$

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