- A$500$
- ✓$3780$
- C$515$
- D$520$
Case-I $a d=b c=0$
Now $\mathrm{ad}=0$
$\Rightarrow$ Total - (When none of a & $d$ is 0 )
$=8^2-1=15$ ways
Similarly bc $=0 \Rightarrow 15$ ways
$\therefore 15 \times 15=225$ ways of $a d=b c=0$
Case-II $a d=b c \neq 0$
either $a=d=b=c \quad$ OR $\quad a \neq d, b \neq d$ but $a d=b c$
${ }^7 \mathrm{C}_1=7$ ways
${ }^7 \mathrm{C}_2 \times 2 \times 2=84$ ways
Total 91 ways
$\therefore|\mathbb{R}|=0 \text { in } 225+91=316 \text { ways }$
$|\mathbb{R}| \neq 0 \text { in } 8^4-316=3780$
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$f(x)=\max \{\sin t: 0 \leq t \leq x\}, \quad 0 \leq x \leq \pi$
$\quad \quad \quad \quad \quad \quad 2+\cos x,\quad \quad \quad \quad x>\pi$
Then which of the following is true?