Let the matrix A and B be defined as A , = , [ * 20 c 3&2 2&1 ] a… - Vidyadip

MCQ

Let the matrix $A$ and $B$ be defined as $A\, = \,\left[ {\begin{array}{*{20}{c}}
3&2 \\
2&1
\end{array}} \right]$ and $B\, = \,\left[ {\begin{array}{*{20}{c}}
3&1 \\
7&3
\end{array}} \right]$ , then the value of $det. \,(2A^9B^{-1}),$ is :-

A
$2$
B
$1$
C
$-1$
✓
$-2$

✓

Answer

Correct option: D.

$-2$

d
$|A|=-1,|B|=2$

$\left| {2{A^9}{B^{ - 1}}} \right| = 4|A{|^9}|B{|^{ - 1}} = - 2$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 3 and 4 . determinant and metrices→STD 12 - 3 and 4 . determinant and metrices — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

$\int_{}^{} {x{{\cos }^2}} xdx = $

Choose the correct answer from the given four options:
The area of the region bounded by the curve y = x + 1 and the lines x = 2 and x = 3 is:

Let $f:[0, \infty) \rightarrow R$ be a continuous function such that $f(x)=1-2 x+\int_0^x e^{x-t} f(t) d t$ for all $x \in[0, \infty)$. Then, which of the following statement (s) is (are) $TRUE$?

$(A)$ The curve $y=f(x)$ passes through the point $(1,2)$

$(B)$ The curve $y=f(x)$ passes through the point $(2,-1)$

$(C)$ The area of the region $\left\{(x, y) \in[0,1] \times R: f(x) \leq y \leq \sqrt{1-x^2}\right\}$ is $\frac{\pi-2}{4}$

$(D)$ The area of the region $\left\{(x, y) \in[0,1] \times R: f(x) \leq y \leq \sqrt{1-x^2}\right\}$ is $\frac{\pi-1}{4}$

${\cot ^{ - 1}}\left[ {\frac{{\sqrt {1 - \sin x} + \sqrt {1 + \sin x} }}{{\sqrt {1 - \sin x} - \sqrt {1 + \sin x} }}} \right] = $

If the function $f:[1,\;\infty ) \to [1,\;\infty )$ is defined by $f(x) = {2^{x(x - 1)}},$ then ${f^{ - 1}} (x)$ is

The points at which the tangents to the curve $y = x^3 - 12x + 18$ are parallel to $x-$axis are:

Let $X_1$ and $X_2$ are optimal solutions of a $\ce{LPP},$ then:

The figure formed by the four points $i + j - k,\,\,\,2i + 3j,$ $3i + 5j - 2k$ and $k - j$ is

Let $\text{f(x)}=|\sin\text{x}|.$ then,

For any real number $\mathrm{x}$, let $|\mathrm{x}|$ denote the largest integer less than or equal to $\mathrm{x}$. Let $\mathrm{f}$ be a real valued function defined on the interval $[-10,10]$ by

$f(x)=\left\{\begin{array}{cc}x-[x] & \text { if }[x] \text { is odd } \\ 1+[x]-x & \text { if }[x] \text { is even }\end{array}\right.$

Then the value of $\frac{\pi^2}{10} \int_{-10}^{10} f(x) \cos \pi x d x$ is