Question
Let there be an A.P. with first term ' $a$ ', common difference ' $d$ '. If $a_n$ denotes in $n^{\text {th }}$ term and $S_n$ the sum of first $n$ terms, find.
$n$ and $S_n$, if $a=5, d=3$ and $a_n=50$.

Answer

Here, we have an A.P. whose $n ^{\text {th }}$ term ( $a _{ n }$ ), first term $(a)$ and common difference $( d )$ are given, We need to find the number of terms $( n )$ and the sum of first n terms ( $S _{ n }$ ).
Here,
First term (a) $=25$
Last term $\left(a_n\right)=50$
Common difference $( d )=3$
So here we will find the value of $n$ using the formula, an $=a+(n-1) d$
So, substituting the values in the above mentioned formula
$50=5+(n-1) 3$
$50=5+3 n-3$
$50=2+3 n$
$3 n=50-2$
Furhter simplifying for $n$,
$3 n=48$
$n=\frac{48}{3}$
$n=16$
Now, here we can find the sum of the n terms of the given A.P., using the formula,
$S_n=\left(\frac{n}{2}\right)(a+1)$
Where, $a=$ the first term
I = the last term
So, for the givne A.P, on substituting the values in the formula for the sum of n terms of an A.P., we get,
$S_{16}=\left(\frac{16}{2}\right)[5+50]$
$=8(55)$
$=440$
Therefore, for the given A.P. $n=16$ and $S_n=440$

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