MCQ
Let $U$ be the universal set containing $700$ elements. If $A, B$ are subsets of $U$ such that $\text{n(A)}=200,\text{ n(B)}=300$ and $\text{n(A}\cap\text{B)}=100.$ Then, $\text{n(A}'\cap\text{B}')=$
  • A
    $400$
  • B
    $600$
  • $300$
  • D
    None of these.

Answer

Correct option: C.
$300$
$\text{n(A}'\cap\text{B}')=\text{n(A}\cup\text{B}')$
$=\text{n(U)}-\text{n(A}\cup\text{B})$
$=700 - 200 + 300 - 100 = 300.$

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