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Let $[ {\varepsilon _0} ]$ denote the dimensional formula of the permittivity of vacuum. If $M =$ mass, $L=$ length, $T =$ time and $A=$ electric current, then:
  • A$\;{\varepsilon _0}=M^{-1}L^{-3}T^2A$
  • B$\;{\varepsilon _0}=M^{-1}L^{-3}T^4A^2$
  • C$\;{\varepsilon _0}=M^{-1}L^2T^{-1}A^{-2}$
  • D${\varepsilon _0}=M^{-1}L^2T^{-1}A$
JEE MAIN 2013, Medium
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