Question
Let $\vec{\text{a}},\vec{\text{b}},\vec{\text{c}},\vec{\text{d}}$ be the position vectors of the four distinct points A, B, C, D. If $\vec{\text{b}}-\vec{\text{a}}=\vec{\text{c}}-\vec{\text{d}}$, then show that ABCD is a parallelogram.
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$\int_0^{\pi / 4} \frac{\sec ^2 x}{3 \tan ^2 x+4 \tan x+1} \cdot d x$
| $x$ | $0$ | $1$ | $2$ | $3$ | $4$ |
| $P ( X =x)$ | $0.45$ | $0.35$ | $0.15$ | $0.03$ | $0.02$ |