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Semiconductors and Semiconductor Devices — Physics STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsSemiconductors and Semiconductor Devices5 Marks
Question
Let $\text{X}=\overline{\text{ABC}}+\overline{\text{BCA}}+\overline{\text{CAB}}.$ Evaluate X for:
  1. $\text{A}=1,\text{B}=0,\text{C}=1$
  2. $\text{A}=\text{B}=\text{C}=1$
  3. $\text{A}=\text{B}=\text{C}=0$
✓

Answer

Given, Output $\text{X}=\overline{\text{ABC}}+\overline{\text{BCA}}+\overline{\text{CAB}}$
  1. $\text{A}=1,\text{B}=0,\text{C}=1$
$\text{X}=1.\Big(\overline{0.1}\Big)+0\Big(\overline{1.1}\Big)+1\Big(\overline1.0\Big)$
$=1.\bar{0}+0.\bar{1}+1.\bar{0}$
$=1.1+0.0+1.1$
$=1+0+1$
$=1+1$
$=1$
  1. $\text{A}=\text{B}=\text{C}=1$
$\text{X}=1\Big(\overline{1.1}\Big)+1\Big(\overline{1.1}\Big)+1\Big(\overline{1.1}\Big)$
$=1.\bar{1}+1.\bar{1}+1.\bar{1}$
$=1.0+1.0+1.0$
$=0+0+0$
$=0$
  1. $\text{A}=\text{B}=\text{C}=0$
$\text{X}=0\Big(\overline{0.0}\Big)+0\Big(\overline{0.0}\Big)+0\Big(\overline{1.1}\Big)$
$=0.\bar{0}+0.\bar{0}+0.\bar{0}$
$=0.1+0.1+0.1$
$=0+0+0$
$=0.$

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