MCQ
Let $y=f(x)=\sin ^3\left(\frac{\pi}{3}\left(\cos \left(\frac{\pi}{3 \sqrt{2}}\left(-4 x^3+5 x^2+1\right)^{\frac{3}{2}}\right)\right)\right)$ .Then, at $x =1$,
  • A
    $2 y^{\prime}+\sqrt{3} \pi^2 y=0$
  • $2 y^{\prime}+3 \pi^2 y=0$
  • C
    $\sqrt{2} y^{\prime}-3 \pi^2 y=0$
  • D
    $y^{\prime}+3 \pi^2 y=0$

Answer

Correct option: B.
$2 y^{\prime}+3 \pi^2 y=0$
b
$y =\sin ^3(\pi / 3 \cos g(x))$

$g(x)=\frac{\pi}{3 \sqrt{2}}\left(-4 x^3+5 x^2+1\right)^{3 / 2}$

$g(1)=2 \pi / 3$

$y^{\prime}=3 \sin ^2\left(\frac{\pi}{3} \cos g(x)\right) \times \cos \left(\frac{\pi}{3} \cos g(x)\right) \times \frac{\pi}{3}(-\sin g(x)) g^{\prime}(x)$

$y^{\prime}(1)=3 \sin ^2\left(-\frac{\pi}{6}\right) \cdot \cos \left(\frac{\pi}{6}\right) \cdot \frac{\pi}{3}\left(-\sin \frac{2 \pi}{3}\right) g^{\prime}(1)$

$g^{\prime}(x)=\frac{\pi}{3 \sqrt{2}}\left(-4 x^3+5 x^2+1\right)^{1 / 2}\left(-12 x^2+10 x\right)$

$g^{\prime}(1)=\frac{\pi}{2 \sqrt{2}}(\sqrt{2})(-2)=-\pi$

$y^{\prime}(1)=\frac{\not \beta}{4} \cdot \frac{\sqrt{3}}{2} \cdot \frac{\pi}{3}$

$\left(\frac{-\sqrt{3}}{2}\right)(-\pi)=\frac{3 \pi^2}{16}$

$y(1)=\sin ^3(\pi / 3 \cos 2 \pi / 3)=-\frac{1}{8}$

$2 y^{\prime}(1)+3 \pi^2 y(1)=0$

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