Let z = i^ 2i , then |z| is (where i = - 1 ) - Vidyadip

MCQ

Let $z$ =${i^{2i}}$ , then $|z|$ is (where $i$ =$\sqrt { - 1}$ )

A
$1$
B
${e^\pi }$
✓
${e^{ - \pi }}$
D
${e^{\frac{\pi }{2}}}$

✓

Answer

Correct option: C.

${e^{ - \pi }}$

c
$z=\left(e^{i \pi / 2}\right)^{2 i}=e^{-\pi}$

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