lf AB then the value of equal, where A(2k, 2, 3), B(k, 1, 5), C(3… - Vidyadip

MCQ

lf $\text{AB}\perp\text{BC}$ then the value of $\lambda$ equal, where A(2k, 2, 3), B(k, 1, 5), C(3 + k, 2, 1):

A
$3$
B
$\frac{1}{3}$
C
$-3$
D
$-\frac{1}{3}$

✓

Answer

$-3$

Solution:

The drs of AB are (k, 1, -2)

The drs of BC are (3, 1, -4)

Since, they are perpendicular, AB.BC = 0

3k + 1 + 8 = 0

k = -3

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