MCQ
lf y = $a e^{\cos ^{-1} x}$, then corresponding to this the differential equation is ______.
- A$\frac{d y}{d x}=\frac{x}{\sqrt{1-x^2}}$
- ✓$\frac{d y}{d x}=\frac{-y}{\sqrt{1-x^2}}$
- C$\frac{d y}{d x}=\frac{\sqrt{1-x^2}}{y}$
- D$\frac{d y}{d x}=\frac{-x}{\sqrt{1-x^2}}$
