Question
Light from a massive star suffers 'gravitational red shift' i.e., its wavelength changes towards the red end due to the gravitational attraction of the star. Obtain the formula for this gravitational red shift using the simple consideration that a photon of frequency v has energy $\text{h}\nu$ (h=planck's constant) and mass $\frac{\text{h}\nu}{\text{c}^2}.$ Estimate the magnitude of the red-shift for light of wavelength $5000\mathring{\text{A}}$ from a star of mass $10^{32}kg$ and radius $10^6km. G = 6.67 \times 10^{-11}Nm^2 kg^{-2}$ and $C = 3 \times 108m s^{-1}$.

Answer

$\text{h}\nu^{'}=\text{h}\nu-\frac{\text{GMh}\nu}{\text{Rc}^2}$i.e., $\nu'=\nu\Big(1-\frac{\text{GM}}{\text{c}^2\text{R}}\Big)$
where $\nu'$ is the shifted frequency.
Now, $\lambda'=\lambda\Big(1+\frac{\text{GM}}{\text{c}^2\text{R}}\Big)$ if $\frac{\text{GM}}{\text{Rc}^2}<1$
i.e., $\lambda'-\lambda=\frac{\lambda\text{GM}}{\text{c}^2\text{R}}=0.371\mathring{\text{A}}$

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