MCQ
$\lim _{n \rightarrow \infty} \frac{3}{n}\left\{4+\left(2+\frac{1}{n}\right)^2+\left(2+\frac{2}{n}\right)^2+\ldots+\left(3-\frac{1}{n}\right)^2\right\}$ is equal to
- A$12$
- B$\frac{19}{3}$
- C$0$
- ✓$19$
$=3 \int \limits_0^1(2+x)^2 d x=27-8=19$
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