= x→π 2 - Vidyadip

MCQ

$ \lim \tan\text{x} = \text{x}→\frac{π}{2}$

A
1
B
0
C
$ \frac{1}{\pi}$
D
does not exisz

✓

Answer

does not exisz

Solution:

$\text{L.H.L}.=\lim \tan\text{x}=+∞ \ \text{x}→\Big(\frac{\pi}{2}\Big)^-$

$\text{R.H.L}.=\lim \tan\text{x}=-∞ \ \text{x}→\Big(\frac{\pi}{2}\Big)^+$

Clearly left hand $ \text{limit} \neq$ right hand limit.

Hence given limit does not exist.

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