MCQ
$\lim _{x \rightarrow 0} \frac{ e ^x+ e ^{-x}-2}{x^2}=$
  • 1
  • B
    -1
  • C
    $\frac{1}{2}$
  • D
    $-\frac{1}{2}$

Answer

Correct option: A.
1
(A)
$\lim _{x \rightarrow 0} \frac{ e ^x+ e ^{-x}-2}{x^2}=\lim _{x \rightarrow 0} \frac{ e ^x+\frac{1}{ e ^x}-2}{x^2}$
$=\lim _{x \rightarrow 0} \frac{\left( e ^x\right)^2-2 e ^x+1}{x^2 e ^x}=\lim _{x \rightarrow 0}\left(\frac{ e ^x-1}{x}\right)^2 \cdot \frac{1}{ e ^x}$
$=(1)^2 \cdot \frac{1}{ e ^0}=1$

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