MCQ
$\lim _{x \rightarrow 0} \frac{e^{2 |\text { sin } x | \mid}-2|\sin x|-1}{x^2}$
  • A
    is equal to -$1$
  • B
    does not exist
  • C
    is equal to $1$
  • is equal to $2$

Answer

Correct option: D.
is equal to $2$
d
$\lim _{x \rightarrow 0} \frac{e^{2 s i n x}-2|\sin x|-1}{x^2}$

$lim _{x \rightarrow 0} \frac{e^{2 s i n x}-2|\sin x|-1}{|\sin x|^2} \times \frac{\sin ^2 x}{x^2}$

Let $|\sin x|=t$

$\lim _{t \rightarrow 0} \frac{e^{2 t}-2 t-1}{t^2} \times \lim _{x \rightarrow 0} \frac{\sin ^2 x}{x^2}$

$=\lim _{t \rightarrow 0} \frac{2 e^{2 t}-2}{2 t} \times 1=2 \times 1=2$

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