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Limits — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsLimits2 Marks
MCQ
$\lim _{x \rightarrow 0} \frac{\log \left(1+\frac{8 x}{3}\right)}{x}$ is equal to
  • ✓
    $\frac{8}{3}$
  • B
    $\frac{-8}{3}$
  • C
    $\frac{3}{8}$
  • D
    $\frac{-3}{8}$
✓

Answer

Correct option: A.
$\frac{8}{3}$
(A)
$\lim _{x \rightarrow 0} \frac{\log \left(1+\frac{8 x}{3}\right)}{x}=\lim _{x \rightarrow 0} \frac{\log \left(1+\frac{8 x}{3}\right)}{\frac{8}{3} x} \cdot \frac{8}{3}$
$=\frac{8}{3}$

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