MCQ
$\lim _{x \rightarrow 0} \frac{\sin x^{\circ}}{x}=$
  • A
    1
  • $\frac{\pi}{180}$
  • C
    does not exist
  • D
    $\frac{\pi}{90}$

Answer

Correct option: B.
$\frac{\pi}{180}$
(B)
$\lim _{x \rightarrow 0} \frac{\sin x^0}{x}=\lim _{x \rightarrow 0} \frac{\sin \frac{\pi x}{180}}{x}=\frac{\pi}{180} \ldots\left[\because x^{\circ}=\frac{\pi x}{180}\right.$ radian $]$

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