MCQ
$\lim _{x \rightarrow 1} \frac{x^8-2 x+1}{x^4-2 x+1}$ equals
  • 3
  • B
    $0$
  • C
    -3
  • D
    1

Answer

Correct option: A.
3
(A)
Applying L-Hospital's Rule, we get
$\lim _{x \rightarrow 1} \frac{x^8-2 x+1}{x^4-2 x+1}=\lim _{x \rightarrow 1} \frac{8 x^7-2}{4 x^3-2}=3$

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