MCQ
$\lim _{x \rightarrow 1}\left(\frac{2}{1-x^2}+\frac{1}{x-1}\right)=$
  • $\frac{1}{2}$
  • B
    $\frac{1}{5}$
  • C
    $\frac{1}{7}$
  • D
    $\frac{1}{11}$

Answer

Correct option: A.
$\frac{1}{2}$
(A)
$\lim _{x \rightarrow 1}\left(\frac{2}{1-x^2}+\frac{1}{x-1}\right)=\lim _{x \rightarrow 1}\left[\frac{2}{(1+x)(1-x)}+\frac{1}{x-1}\right]$
$=\lim _{x \rightarrow 1}\left[\frac{1-x}{(1+x)(1-x)}\right]=\frac{1}{2}$

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