_ x 2 x^2-4 x^2-x-2 = - Vidyadip

MCQ

$\lim _{x \rightarrow 2} \frac{x^2-4}{x^2-x-2}=$

A
$\frac{17}{5}$
B
$\frac{23}{6}$
✓
$\frac{4}{3}$
D
$\frac{13}{2}$

✓

Answer

Correct option: C.

$\frac{4}{3}$

(C)
Applying L-Hospital's Rule, we get
$\lim _{x \rightarrow 2} \frac{x^2-4}{x^2-x-2}=\lim _{x \rightarrow 2} \frac{2 x}{2 x-1}=\frac{4}{3}$

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