_ x 2 x^2-7 x+2 x^2+5 = - Vidyadip

MCQ

$\lim _{x \rightarrow 2} \frac{x^2-7 x+2}{x^2+5}=$

A
$\frac{-2}{5}$
B
$\frac{-7}{9}$
✓
$\frac{-8}{9}$
D
$\frac{-7}{8}$

✓

Answer

Correct option: C.

$\frac{-8}{9}$

(C)
$\lim _{x \rightarrow 2} \frac{x^2-7 x+2}{x^2+5}=\frac{2^2-7(2)+2}{2^2+5}=\frac{-8}{9}$

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