Download App

Limits — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsLimits2 Marks
MCQ
$\lim _{x \rightarrow 3} \frac{\sqrt{x^2+10}-\sqrt{19}}{x-3}$ is equal to
  • A
    $0$
  • ✓
    $\frac{3}{\sqrt{19}}$
  • C
    $\frac{6}{\sqrt{19}}$
  • D
    $\sqrt{19}$
✓

Answer

Correct option: B.
$\frac{3}{\sqrt{19}}$
(B)
Applying L-Hospital's rule, we get
$\lim _{x \rightarrow 3} \frac{\sqrt{x^2+10} \sqrt{19}}{x-3}=\lim _{x \rightarrow 3} \frac{1}{2 \sqrt{x^2+10}}(2 x)=\frac{3}{\sqrt{19}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Limits→Limits — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

If $\sin x+\sin y=\frac{1}{2}$ and $\cos x+\cos y=1$, then $\tan (x+y)=$
→
$\big(\sqrt{-2}\big)\big(\sqrt{-3}\big)$ is equal to :
→
Square roots of $-48-14 i$ are
→
The value of $\cos 57^{\circ}+\sin 27^{\circ}$ is equal to
→
$\lim _{x \rightarrow \infty} \frac{x^n}{ e ^x}=0$ for
→
From a pack of 52 cards, the cards are drwan till an ace appears. Probability that an ace does not come in first 26 cards is,
→
The value of $\frac{\cos3\text{x}}{2\cos2\text{x}-1}$ is equal to :
→
If $A =\tan 6^{\circ} \tan 42^{\circ}$ and $B =\cot 66^{\circ} \cot 78^{\circ}$, then
→
A point P moves such that sum of the distances from point (c, 0) and (c, 0) is 2a, then equation of locus of P such that $b^2=a^2-c^2$, is
→
The value of $\cos 15^{\circ}-\sin 15^{\circ}$ is equal to
→