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Limits — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsLimits2 Marks
MCQ
$\lim _{x \rightarrow-3} \frac{\sqrt{x^2+7}-4}{x+3}$ is equal to
  • ✓
    $-\frac{3}{4}$
  • B
    $\frac{3}{4}$
  • C
    $\frac{3}{9}$
  • D
    $\frac{-3}{9}$
✓

Answer

Correct option: A.
$-\frac{3}{4}$
(A)
Applying L-Hospital's Rule, we get
$\lim _{x \rightarrow-3} \frac{\sqrt{x^2+7}-4}{x+3}=\lim _{x \rightarrow-3} \frac{1}{2 \sqrt{x^2+7}}(2 x)=\frac{-3}{4}$

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