MCQ
$\lim _{x \rightarrow 3}\left(\frac{x-3}{\sqrt{x-2}-\sqrt{4-x}}\right)=$
  • 1
  • B
    2
  • C
    -1
  • D
    -2

Answer

Correct option: A.
1
(A)
$\lim _{x \rightarrow 3}\left(\frac{x-3}{\sqrt{x-2}-\sqrt{4-x}}\right)$
$=\lim _{x \rightarrow 3} \frac{(x-3)(\sqrt{x-2}+\sqrt{4-x})}{(\sqrt{x-2}-\sqrt{4-x})(\sqrt{x-2}+\sqrt{4-x})}$
$=\lim _{x \rightarrow 3} \frac{(x-3)(\sqrt{x-2}+\sqrt{4-x})}{2(x-3)}$
$=1$
Alternate method:
Apply L-Hospital's rule.

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