MCQ
$\lim _{x \rightarrow \frac{\pi}{2}} \frac{2 x-\pi}{\cos x}=$
- A2
- B1
- ✓-2
- DNone of these
✓
Answer
Correct option: C.
-2
(C)
$\lim _{x \rightarrow \frac{\pi}{2}} 2\left[\frac{x-\frac{\pi}{2}}{\sin \left(\frac{\pi}{2}-x\right)}\right]=-2$
Alternate method:
Apply L-Hospital's rule.
$\lim _{x \rightarrow \frac{\pi}{2}} 2\left[\frac{x-\frac{\pi}{2}}{\sin \left(\frac{\pi}{2}-x\right)}\right]=-2$
Alternate method:
Apply L-Hospital's rule.
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