MCQ
$\lim _{x \rightarrow \frac{\pi}{6}} \frac{3 \sin x-\sqrt{3} \cos x}{6 x-\pi}$ equals
  • A
    $\sqrt{3}$
  • $\frac{1}{\sqrt{3}}$
  • C
    $-\sqrt{3}$
  • D
    $-\frac{1}{\sqrt{3}}$

Answer

Correct option: B.
$\frac{1}{\sqrt{3}}$
(B)
Applying L-Hospital's Rule, we get
$\lim _{x \rightarrow \frac{\pi}{6}} \frac{3 \sin x-\sqrt{3} \cos x}{6 x-\pi}=\lim _{x \rightarrow \frac{\pi}{6}}\left(\frac{3 \cos x+\sqrt{3} \sin x}{6}\right)$
$=\frac{3 \cdot \frac{\sqrt{3}}{2}+\sqrt{3 \cdot \frac{1}{2}}}{6}$
$=\frac{1}{\sqrt{3}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free