MCQ
$\lim _{x \rightarrow \infty}\left(\sqrt{x^2+1}-x\right)$ is equal to
  • A
    1
  • B
    -1
  • $0$
  • D
    2

Answer

Correct option: C.
$0$
(C)
On rationalising, we get
$\lim _{x \rightarrow \infty}\left(\sqrt{x^2+1}-x\right)=\lim _{x \rightarrow \infty} \frac{x^2+1-x^2}{\sqrt{x^2+1}+x}$
$=\lim _{x \rightarrow \infty} \frac{1}{\sqrt{x^2+1}+x}=0$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free