Limiting molar conductivity of CH_3COOH (i.e. _ m ,(C H_3 COOH) ^… - Vidyadip

MCQ

Limiting molar conductivity of $CH_3COOH$ (i.e. $\Lambda _{m\,(C{H_3}COOH)}^o$ is equal to

A
$\Lambda _{m\,(C{H_3}COOH)}^o + \Lambda _{m\,(C{H_3}COONa)}^o - \Lambda _{m\,(NaOH)}^o$
✓
$\Lambda _{m\,(C{H_3}COONa)}^o + \Lambda _{m\,(HCl)}^o - \Lambda _{m\,(NaCl)}^o$
C
$\Lambda _{m\,(C{H_3}COONa)}^o + \Lambda _{m\,(NaCl)}^o - \Lambda _{m\,(NaOH)}^o$
D
$\Lambda _{m\,(NaOH)}^o + \Lambda _{m\,(NaCl)}^o - \Lambda _{m\,(C{H_3}COONa)}^o$

✓

Answer

Correct option: B.

$\Lambda _{m\,(C{H_3}COONa)}^o + \Lambda _{m\,(HCl)}^o - \Lambda _{m\,(NaCl)}^o$

b

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