As their is not any $x$ term in the denominator,
we can directly substitute the value of $x$ as $0.$
Thus, we have $\lim_\limits{\text{x} \rightarrow 0}\frac{2\text{x}^2+3\text{x}+4}{2}$
$=\frac { 2.0+3.0+4 }{ 2 }$
$=\frac{4}{2}$
$=2$
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