MCQ
$ \lim_\limits{\text{x} \rightarrow 0}\frac{3\sin(2\text{x}^2)}{\text{x}^2}= A$ then the value of $A$ is:
  • A
    $2$
  • B
    $4$
  • $6$
  • D
    $8$

Answer

Correct option: C.
$6$
$ \lim_\limits{\text{x} \rightarrow 0}\frac{3\sin(2\text{x}^2)}{\text{x}^2}=$
$ \lim_\limits{\text{x} \rightarrow 0}\frac{2\ *\ 3\sin(2\text{x}^2)}{\text{2x}^2}=6$

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