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Limits and Derivatives — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsLimits and Derivatives1 Mark
MCQ
$\lim_\limits{\text{x} \rightarrow -1\frac{\text{x}^2}{\text{x}-1}}=...........$
  • A
    $0$
  • B
    $1$
  • ✓
    $ \frac{-1}{2}$
  • D
    $-2$
✓

Answer

Correct option: C.
$ \frac{-1}{2}$
$=\lim_\limits{\text{x} \rightarrow -1\frac{\text{x}^2}{\text{x}-1}}$
Substituting $x = -1$
we get, $ \displaystyle \lim _{ \text{x}\rightarrow -1 } \frac{\text{x}^2}{\text{x}-1}= \frac { { (-1) }^2 1 }{ -1-1 } = -\frac {1}{2}$

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