_ x 0 2x^2+3x+4 2 = - Vidyadip

MCQ

$\lim_\limits{\text{x} \rightarrow 0}\frac{2\text{x}^2+3\text{x}+4}{2}=$

A
2
B
1
C
$ 3\sqrt{5}$
D
$ 2\sqrt{5}$

✓

Answer

2

Solution:

As their is not any x term in the denominator,

we can directly substitute the value of x as 0.

Thus, we have $\lim_\limits{\text{x} \rightarrow 0}\frac{2\text{x}^2+3\text{x}+4}{2}$

$ =\frac { 2.0+3.0+4 }{ 2 }$

$ =\frac{4}{2}=2$

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