_ x -1 x^2 x-1 =______. - Vidyadip

MCQ

$\lim_\limits{\text{x} \rightarrow -1\frac{\text{x}^2}{\text{x}-1}}=$______.

A
0
B
1
C
$ \frac{-1}{2}$
D
-2

✓

Answer

$ \frac{-1}{2}$

Solution:

$=\lim_\limits{\text{x} \rightarrow -1\frac{\text{x}^2}{\text{x}-1}}$

Substituting x = -1

we get, $ \displaystyle \lim _{ \text{x}\rightarrow -1 } \frac{\text{x}^2}{\text{x}-1}= \frac { { (-1) }^2 1 }{ -1-1 } = -\frac {1}{2}$

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