MCQ
$ \lim\limits_{\text{x}→3}\ 2\text{x}^2−3\text{x}−5 =$
- A4
- B3
- C-4
- D-3
Solution:
$ \lim\limits_{\text{x}→3}\ 2\text{x}^2−3\text{x}−5 $
$ = 2(3)^2 - 3(3) - 5$
= 18 - 9 - 5
= 4
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If x is a real number and |x| < 3, then:
$\text{x}\geq3$
$-3<\text{x}<3$
$\text{x}\leq-3$
$-3\leq\text{x}\leq3$