Question
Locate the image formed by refraction in the situation shown in figure.
✓
Answer
$\mu_1=1, \ \mu_2=1.5,$R = 20cm (Radius of curvature), u = -25cm$\therefore \ \frac{\mu_2}{\text{v}}-\frac{\mu_1}{\text{u}}=\frac{\mu_2-\mu_1}{\text{R}}$
$\Rightarrow\frac{1.5}{\text{v}}=\frac{0.5}{20}-\frac{1}{25}=\frac{1}{40}-\frac{1}{25}=\frac{-3}{200}$
$\Rightarrow \ \text{v}=200\times0.5=-100\text{cm}.$
So, the image is 100cm from (P) the surface on the side of S.
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