MCQ
Magnitude of $K.E.$ in an orbit is equal to
- ✓Half of the potential energy
- BTwice of the potential energy
- COne fourth of the potential energy
- DNone of these
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${\left[ Ni ( CN )_4\right]^{2-},\left[ Ni ( CO )_4\right],\left[ NiCl _4\right]^{2-}}$
${\left[ Fe ( CN )_6\right]^{4-},\left[ Cu \left( NH _3\right)_4\right]^{2+}}$
${\left[ Fe ( CN )_6\right]^{3-} \text { and }\left[ Fe \left( H_2O\right)_6\right]^{2+}}$
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - {C_6}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{HBr\,/\,Peroxide}}'A'$
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - {C_6}{H_5}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{HBr}]{}'B'$