- A${C_2}{H_2}$
- ✓$C{H_4}$
- C${H_2}S$
- D$CO$
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The functional group present in $B$ and name of the reaction would be
$C{{H}_{3}}CN+2H\underset{\text{Ether}}{\mathop{\xrightarrow{HCl}}}\,X\underset{{{H}_{2}}O}{\mathop{\xrightarrow{\text{Boiling}}}}\,Y;$ the term $Y$ is:
$O(g) + e^- = O^-(g)$ $\Delta {H_{eg}} = - 142\,kJ\,mo{l^{ - 1}}$
$O^-(g) + e^- = O^{2-}(g)$ $\Delta {H_{eg}} = +844\,kJ\,mo{l^{ - 1}}$
This is because
Assertion $A$ :$[6]$ Annulene.$[8]$ Annulene and cis - $[10]$ Annulene, are respectively aromatic, not-aromatic and aromatic.
Reason $R$ : Planarity is one of the requirements of aromatic systems.
In the light of the above statements, choose the most appropriate answer from the options given below.