MCQ
Main reason for brown ring test of $NO_3^-$ is
- ANegligible tendency of $FeSO_4$ to form complex
- ✓Reducing power of $FeSO_4$ to convert $NO_3^-$ to $NO$
- CDecomposition of $FeSO_4$ to give $SO_2$ gas
- DOxidising property of $FeSO_4$
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[Assume $100 \%$ ionisation of the complex and $CaCl _{2},$ coordination number of $Cr$ as $6,$ and that all $NH _{3}$ molecules are present inside the coordination sphere $]$
